free oak firewood near me

free oak firewood near me

Matematika Sekolah Menengah Pertama bantu jawab ya kakak kakak onlenn:))
makasih banyakkk<33333​

bantu jawab ya kakak kakak onlenn:))
makasih banyakkk<33333​

Jawaban:

Teorema Pythagoras

1. Alas (a) = 10 cm

Tinggi (t) = 24 cm

sisi miring ( x ) = ?

penyelesaian:

[tex] {x}^{2} = {a}^{2} + {t}^{2} [/tex]

[tex]x = \sqrt{ {a}^{2} + {t}^{2} } [/tex]

[tex]x = \sqrt{ {10}^{2} + {24}^{2} } [/tex]

[tex]x = \sqrt{100 + 576} [/tex]

[tex]x = \sqrt{676} [/tex]

[tex]x = 26 \: cm[/tex]

2. sisi miring ( x) = 12 cm

alas (a) = 8 cm

tinggi (t) = ..?

Penyelesaian:

[tex] {t}^{2} = {x}^{2} - {a}^{2} [/tex]

[tex]t = \sqrt{ {x}^{2} - {a}^{2} } [/tex]

[tex]t = \sqrt{ {12}^{2} - {8}^{2} } [/tex]

[tex]t = \sqrt{144 - 64} [/tex]

[tex]t = \sqrt{80} [/tex]

[tex]t = \sqrt{16 \times 5} [/tex]

[tex]t = \sqrt{16} \times \sqrt{5} [/tex]

[tex]t = 4 \sqrt{5} [/tex]

3. Alas (a) = 5 cm

sisi miring (x) = 13 cm

tinggi (t)= ..?

Penyelesaian:

[tex] {t}^{2 } = {x}^{2} - {a}^{2} [/tex]

[tex]t = \sqrt{ {x}^{2} - {a}^{2} } [/tex]

[tex]t = \sqrt{ {13}^{2} - {5}^{2} } [/tex]

[tex]t = \sqrt{169 - 25} [/tex]

[tex]t = \sqrt{144} [/tex]

[tex]t = 12 \: cm[/tex]

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